Time and distance sums for competitive Exams

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Introduction

In this competitive world, everyone's ambition is to achieve something good in their life. Most people's main goal is to prepare for competitive exams, get selected, and lead a good life. If your goal is to do that visit Nithra Jobs sites. It provides simple speed time and distance questions with answers so, you can reach your destination faster. Here we have given the formula of time and distance. We have already learned during our school days, Time = distance/speed, we can recall our basic skills with some more questions. Learn it quickly with the help of these time speed and distance formulas to improve your aptitude skill.

Time and Distance

Formulas:

1. Speed, Time and Distance:

Speed = Distance / Time

Time = Distance / Speed

Distance = Speed * Time

2. km/hr to m/sec conversion:

x km/hr = (x * 5/18) m/sec.

3. m/sec to km/hr conversion:

x m/sec =(x * 18/5) km/hr.

4. If the ratio of the speeds of A and B is a : b, then the ratio of the times taken by them to cover the same distance is

(1/a) : (1/b) or b : a

5. Suppose a man covers a certain distance at x km/hr and an equal distance at y km/hr. Then, the average speed during the whole journey is

2xy/( x + y) km/hr

Example Sums

1. A man covers X km in t hours at a speed of S km/hr; another man covers X/2 km in 2t hours at a speed of R km/hr. Then the ratio S:R equals

Answer: 4 : 1.

Explanation:

Distance covered by 1st man at S km/hr = x km

Time taken by him = t hours.

∴ Speed = Distance / Time

S = x / t km/hr.

Distance covered by 2nd man at R km/hr = ( x / 2 ) km

Time taken by him = 2t hours.

∴ Speed covered by R is R = ( x / 2 ) * ( 1 / 2t ) km/hr

R = ( x / 4t ) km/hr

Required ratio = S : R

= ( x / t ) : ( x / 4t )

= 1 : ( 1 / 4 )

= 4 : 1

The ratio is 4 : 1.

2. A car starts at 10 am with a speed of 50 km/hr. Due to the problem with the engine, it reduces its speed to 10 km/hr for every 2 hours. After 11 am, the time taken to cover 10 km is:

Answer: 13 minutes and 20 seconds.

Explanation:

Initial speed of the car = 50km/hr

Due to an engine problem, speed is reduced to 10km for every 2 hours (i.e., 5 km per hour).

Speed of the car at 11 am is = ( 50 - 5 )

= 45 km/hr

Time to cover 10 km at 45 km/hr = Distance / speed

= ( 10 / 45 ) hours.

= ( 2 / 9 ) hours

= ( 2 / 9 ) * 60 minutes

= ( 40 / 3 ) minutes

= 13 minutes + 1/3 minutes

= 13 minutes + 1/3 * 60 seconds

= 13 minutes and 20 seconds.

Time taken to cover 10 km is 13 minutes and 20 seconds.

3. Two train travel in opposite directions at 24 kmph and 36 kmph and a man sitting in a slower train passes the faster train in 9 seconds. Then length of the faster train is?

Answer: 150 m

Explanation:

Given data,

Time = 9 seconds,

Relative speed = Sum of speeds

( 24 + 36 )

= 60 km / hr

= 60 * (5 / 18) m / sec

= 50 / 3 m / sec

Using the formula, distance = speed * time

Length of the faster train = (50 / 3) * 9

= 150 m

Length of the faster train is 150 m.

4. Excluding stoppages, the speed of a bus is 30 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

Answer: 20 min

Explanation:

Due to stoppages, it covers ( 45 - 30 ) = 15 km less

Time taken to cover 15 km = distance/speed

= ( 15 / 45) * 60 min

= 20 min

The bus stop per hour for 20 minutes.

5. Three trains are running from place A to another place B. Their speeds are in the ratio of 6 : 3 : 5. The time ratio to reach B by trains will be?

Answer: 5 : 10 : 6

Explanation:

Three trains are running from place A to B.

Ratio of speeds = 6 : 3 : 5

∴ Ratio of times taken [ t = distance/speed or t indirectly proportional to s when distance is same]= ( 1 / 6 ) : ( 1 / 3 ) : ( 1 / 5 )

LCM for 6, 3, and 5 = 30

= ( 1 / 6 ) * 30 : ( 1 / 3 ) * 30 : ( 1 / 5 ) * 30

= 5 : 10 : 6

The time ratio to reach B by trains will be 5 : 10 : 6.

Conclusion

In this article, we have seen the speed time and distance maths problems to develop your aptitude skills. We hope it enhances your knowledge. The time and distance sums are really interesting and the easiest ones that everyone can understand quickly. Ready to prepare speed, distance, and time questions for upcoming exams. These speed, time, and distance problems will be useful for preparing for competitive exams and also for your higher studies.